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Firefox File Edit View History Bookmarks Yahoo! Tools Window Help # O % 4)) 99% Tue 4:15 PM Sloan Lundberg a University of Memphis - PH Mathway | Math Problem S..G Chegg Study | Guided SoltY My computer won't let me t... ii 3 www.saplinglearning.com/ibiscms/modibis/view.php?id-2081767 a ac wont let me take a screen shot Pinterest y Twitter t Apple c Most Visited Building a succes. BuzzFeed Facebook Sapling Learning Organic Chemistry Shark Tracking Yahoo! Google Maps .. YAHOO! my mac wont let me take a screen shot -Print Calculator -d Periodic Table Question 8 of 13 ter an untortunate accident at a locai warenouse you have been contracted to determine the caus A jib crane collapsed and injured a worker. An image of this type of crane is shown in the figure below The horizontal steel beam had a mass of 88.50 kg per meter of length and the tension in the cable was T- 12170 N. The crane was rated for a maximum load of 454.5 kg. If d 5.000 m, s 0.450 m, x-1.650 m and h 2.250 m, what was the magnitude of m (the load on the crane) before the collapse? What was the magnitude of force at the attachment point P? The acceleration due to gravity is g = 9.810 m/s2 Number Number Previous Give Up & View Solution e Check Answer ion Check Answx Exit Next Exit

Explanation / Answer

  Sum the moments about P:
0 = T(d - s)sin - W(d - x) - F(d/2)
= arctan(h/(d-s)) = arctan(2.25 / 4.55) = 26
where F is the weight of the beam.
0 = 12170N*4.55m*sin26º - W*3.35m - 88.50kg/m*5.000m*9.8m/s²*5.000m/2
3.35W =13432 N
W =4009 N load

(b) sum the vertical forces:
Fv + Tsin - W - 88.50kg/m*5.000m*9.8m/s² = 0
Fv + 12170N*sin26 - 4009N - 4747N = 0
Fv = 3421 N vertical force at P

sum the horizontal forces:
Fh - Tcos = 0
Fh - 12170N*cos26º = 0
Fh = 10938N horizontal force at P

mag P = (10938² + 3421²) N = 11 460 N total reaction at P

Since 1000 lb 4450 N,

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