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3-11 AM Thu Sep 20 a access1.lon-capa.uiuc.edu Science Science of Qirat Sun and Mo... for One Day Mens Pants... ton On Men cE 502 Bad Prelecture... 2-25 Flash Sign Up Quiz3 LON-C. Taymur Taymur Hussain Student-section: ALI Main Menu Contents Grades MCB 450 Fall 2018 | Messages Courses Help Logout Course Contents. Homework 3 4 (2 pts3 Timer NotesEvaluate Feedback Print The purification table shown here lists procedures (1-5) that a biochemist used to purify a new enzyme. The columns give the total amount of protein recovered after each step (in milligrams) and the total amount of enzyme activity (in units of activity) recovered after each step, Procedure Total protein Activity 8,000 7,500 450 1. Crude cellular extract 232,000 105,000 102,000 2. Salt fractionation total activity in active fractions) 4. Gel filtration chromatography 75 96,000 (total activity in active fractions) 5. Affinity chromatography 90,000 a) Which procedure was the least effective, i.e. which step gave the least fold purification of protein, because it either didn't remove much protein, or because it caused a major loss in total enzyme activity, or both? O Anion exchange chromatography O Gel filtration chromatography OPreparation of the crude cellular extract O Affinity chromatography O Salt fractionation Submit AnsAnswer Submitted: Your final submission will be graded after the due date. Tries 1/99 Previous Tries b) Using information given in the purification table, you can calculate what fold purification was ultimately achieved for the enzyme. Which of answer options corresponds most closely to the final fold purification? O 621 O 11 O 1,600 0 91 O 46,400 Submit AnsrAnswer Submitted: Your final submission will be graded after the due date. Tries 1/99 Previous Tries Post Discussion Send Feedback

Explanation / Answer

a) By table we can see that affinity chromatography has extracted least amount of protein due to which it is least effective of all.

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