In a popular amusement park ride, a rotating cylinder of radius R = 2.40 m is se
ID: 1471518 • Letter: I
Question
In a popular amusement park ride, a rotating cylinder of radius R = 2.40 m is set in rotation at an angular speed of 4.90 rad/s, as in the figure shown below. The floor then drops away, leaving the riders suspended against the wall in a vertical position. What minimum coefficient of friction between a rider's clothing and the wall is needed to keep the rider from slipping? Hint: Recall that the magnitude of the maximum force of static friction is equal to sn, where n is the normal force—in this case, the force causing the centripetal acceleration.
Explanation / Answer
the normal acting on the rider = Fc = m*R*w^2
frictional force = f = u*Fc = u*m*R*w^2
the weight of the rider is balanced by frictional force
f = W
u*m*R*w^2 = m*g
u*R*w^2 = g
u*2.4*4.9^2 = 9.8
u = 0.17
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