explain ..-11 points SerpSE9 19 P 011 MI FB My Notes O As Y My Notes Ask Your T
ID: 1471953 • Letter: E
Question
explain
Explanation / Answer
given
initial length, L1 = 34 m
T1 = -20 C
T2 = 30 C
coefficient of linera expansion of copper, alfa = 17*10^-6 C^-1
final length, L2 = ?
we know, delta_L = L1*alfa*(T2-T1)
delta_L = L1*alfa*(T2-T1)
= 34*17*10^-6*(30-(-20))
= 0.0289 m
= 2.89 cm
===============================
given
P = 1*10^-9 pa
V = 1.4 m^3
T = 30 C
= 30 + 273
= 303 K
let n is the no of oles of the gas.
use ideal gas equation
P*V = n*R*T
==> n = P*V/(R*T)
= 1*10^-9*1.4/(8.314*303)
= 5.557*10^-13 mol
we know, no of moleculed, N = n*NA (here NA is avagadro's number)
= 5.557*10^-13*6.023*10^23
= 3.345*10^11
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.