Some salvage divers are raising a rectangular box of treasure measuring 1m X1.3m

Question

Some salvage divers are raising a rectangular box of treasure measuring 1m X1.3m x 1.9m from the bottom of the sea. They are using a cable which can handle a maximum force of 10000N without breaking. They raise the treasure from the bottom of the ocean at a constant speed. All goes well while the treasure is rising through the water but much to the despair of the salvors as soon as the treasure is clear of the water the cable breaks, dropping the treasure back into the briny deep. What are the maximum and minimum possible weights of the lost treasure? Answer Mmax =3400kg Mmin=1000kg show work

Explanation / Answer

Fnet = T + Fb - W = m*a

as the speed is constant

acceleration = a = 0

T = Fb + W

T = (rho*V*g)+(M*g)

In water

10000 + (1000*1*1.3*1.9*9.8) = (Mmax*9.8)

Mmax = 3490 N

-

In air Fb = 0

10000 + = (Mmin*9.8)

Mmin = 1020 Kg

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