a 250-g weight is tied to visuals n/ibiscms/mod/ibis/wiew php?id-2195445 101 . F
ID: 1472195 • Letter: A
Question
a 250-g weight is tied to visuals n/ibiscms/mod/ibis/wiew php?id-2195445 101 . Fal115 . APRELEV Acthites and Due Dates HW: Rotat on Gradebook 11/30/2015 11:55 PM25/100 Print Calculotor CalculatorPeriodic Table Periodic Table uestion 3 of 4 Mape apling learming A 250-g weight is tied to a piece of thread wrapped around a spool, which is suspended in such a way that it can rotate freely. When the weight is released, it accelerates toward the floor as the thread unwinds. Assume that the spool can be treated as a uniform solid cylinder of radius R 3 am and mass 100 g Find the tension in the thread and the magnitude of the acceleration of the weight as it descends. Assume the thread has negligible mass and does not slip or stretch as it unwinds -3 cm Number M= 100 g ' acceleration- Number tension I N I mw = 250 + Previous Check Answer Next Ext Hint acy policy terms of uExplanation / Answer
a) mg - T = ma
0.25*9.8 - T = 0.25*a
T = 2.45 - 0.25*a
torque causes cylinder to accelerate
torque = I*alpha
I = 0.5*Mr^2
alpha = a/r
torque = 0.5*Mr^2*a/r
torque = 0.5*M*r*a
and also torque = T*r
T*r = 0.5*M*r*a
2.45 - 0.25*a = 0.5*0.1*a
2.45 = 0.05*a + 0.25*a
a = 2.45/0.3 = 8.167 m/s^2
b) T = 2.45 - 0.25*a
T = 2.45 - 0.25*8.167 = 0.408 N
Related Questions
Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.