Five identical resistors, each of resistance R, are connected in series to a bat

Question

Five identical resistors, each of resistance R, are connected in series to a battery, and a total current of 5.84 A flows in the circuit. Now, another resistor of resistance R is added to the circuit, in parallel with the rest of the resistors. Find the new total current in the circuit. I = In the original circuit: suppose another resistor of resistance R is added to the circuit, in series with the battery. Find the new total current in the circuit. I = Five identical resistors, each of resistance R, are connected in parallel to a battery, and a total current of 5.84 A flows in the circuit. Now, another resistor of resistance R is added to the circuit, in parallel with the rest of the resistors. Find the new total current in the circuit. I = In the original circuit: suppose another resistor of resistance R is added to the circuit, in series with the battery. Find the new total current in the circuit. I =

Explanation / Answer

Let E be the emf of the battery:

Resistance of each resistor=R

current I= 2.86 A

(a)

Total= 5R

so emf= E=I 5R = (5.84)(5)R= 29.20R

New current in the circuit I'=E/(6R) =E/6R=4.87 A

(b)

Total resistance = R/5

so emf = E = I (R/5) = 5.84 (R/5)= 1.17 R

New current in the circuit I'= E (R/6) = 7.02 A

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