. A 200 kg object and a 500 kg object are separated by 0.4 m and are held in pla
ID: 1472708 • Letter: #
Question
. A 200 kg object and a 500 kg object are separated by 0.4 m and are held in place. You may assume that the 200 kg object is on the left. (a) Find the net gravitational force exerted by these objects on a 50 kg object placed exactly midway between them. (b) Determine the gravitational field at the location of the 50 kg object. (c) The 50 kg object is removed and a 60 kg object is placed there instead. Determine its acceleration. Hint: This should take very little work. (d) At what position (other than infinitely far away) can the 50 kg object or the 60 kg object be placed so as to experience a net force of zero?
Explanation / Answer
m1 = 200 kg
m2 = 500 kg
m3 = 50 kg
r1 = 0.2 m
r2 = 0.2 m
Fnet = F2 - F1
Fnet = G*m2*m3/r2^2 - G*m1*m3/r3^2
Fnet = (6.67*10^-11*500*50/0.2^2) - (6.67*10^-11*200*50/0.2^2)
Fnet = 2.5*10^-5 N
b)
g = Fnet/m3 = 5*10^-7 N/kg
c)
a = 5*10^-7 N/kg
d)
let at a distance x from 500 kg the net force = 0
Fnet = 0
(6.67*10^-11*500*50/x^2) = (6.67*10^-11*200*50/(0.4-x)^2)
x = 0.24 m
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.