Three resistors, 10.1 , 51.6 , and R, are connected in series with a 24.0 V batt

Question

Three resistors, 10.1 , 51.6 , and R, are connected in series with a 24.0 V battery. The total current flowing through the battery is 0.130 A. Calculate the value of resistance R. Calculate the potential difference across the 10.1 resistor. Calculate the potential difference across the 51.6 resistor. Calculate the potential difference across R. If the voltage of the battery had been smaller than 24.0 V, would the value of resistance R have been larger or smaller? A) The value of resistance R would have been smaller. B) The value of resistance R would have been larger.

Explanation / Answer

ohm's law

V= IR

Rresult = 10.1+51.6+R = 61.7+R = 24/.13 = 184.61 ohm

=> R = 122.91 ohm

potential difference across the 10.1 resistor = .13*10.1 = 1.313 volt

potential difference across the 51.6 resistor = .13*51.6 = 6.708 volt

potential difference across R=122.91 ohm = .13*122.91 = 15.9783 volt

If the voltage of the battery had been smaller than 24.0 V then the value of resistance R would have been smaller.

because V = IR

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