Two slits separated by a distance of d = 0.130 mm are located at a distance of D

Question

Two slits separated by a distance of d = 0.130 mm are located at a distance of D = 2.39 m from a screen. The screen is oriented parallel to the plane of the slits. The slits are illuminated by a monochromatic and coherent light source with a wavelength of lambda = 624 nm. A wave from each slit propagates to the screen. The interference pattern shows a peak at the center of the screen (m = 0) and then alternating minima and maxima. What is the path length difference between the waves at the first maximum (m = 1) on the screen? At what angle from the beam axis will the first (m = 1) maximum appear?

Explanation / Answer

1.

At First Maxima, Path Length is given by 1*Lambda = 624 nm (or) 0.624 micro meters

2. dsintheta = Lambda

sin theta = Lambda/d = 624 *10^-9/0.13*10^-3 = 0.0048 radians = 0.0015 degrees

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