Exercise 10.9 The flywheel of an engine has a moment of inertia 2.20 kgm2about i

ID: 1473743 • Letter: E

Question

Exercise 10.9

The flywheel of an engine has a moment of inertia 2.20 kgm2about its rotation axis.

Part A

What constant torque is required to bring it up to an angular speed of 370 rev/min in a time of 7.60 s , starting from rest?

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Part B

What is its final kinetic energy?

Exercise 10.9

The flywheel of an engine has a moment of inertia 2.20 kgm2about its rotation axis.

Part A

What constant torque is required to bring it up to an angular speed of 370 rev/min in a time of 7.60 s , starting from rest?

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Part B

What is its final kinetic energy?

Given that

The flywheel of an engine has a moment of inertia (I) = 2.20 kgm2

The initial angualr speed (wo) =0

The angular speed at a time t is (wt) =370 rev/min =38.73rad/s

The time t =7.60s

We know that

wt =wo+alphat

alpha =wt/t =38.73/7.60 =5.096rad/s2

The torque is required to bring it up to an angular speed of 370 rev/min in a time of 7.60 s , starting from rest is

t =I*alpha =( 2.20 kgm2)(5.096rad/s2)=11.21N.m

Now the final kinetic energy is given by

KE =(1/2)Iwt2 =0.5*(2.20)(38.73)2 =1650J

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