On January 22, 1943, the temperature in Spearfish, South Dakota, rose from -4.20

Question

On January 22, 1943, the temperature in Spearfish, South Dakota, rose from -4.20 degree F to 45.2 degree F in just 2 minutes. What was the temperature change in Celsius degrees and in kelvins? Answer in the order indicated. Separate your answers using comma. The temperature in Browning, Montana, was 44.2 degree F on January 23, 1916, and the next day it plummeted to -56.1 degree F. What was the temperature change in Celsius degrees and in kelvins? Answer in the order indicated. Separate your answers using comma.

Explanation / Answer

45.2 - (-4.2) = 49.4 F
(5/9) x 49.4= 27 C/K

44.2 - (-56.10) = 100.3
(5/9) x 100.3 = 55.72 C/K

NOTE: 100 deg C (or K) between freezing of water and boiling of water (0 deg C and 100 deg C)
180 deg F between freezing of water and boiling of water (32 deg F and 212 deg F)
100/180 = 5/9
Since K = C + 273.15 the difference in K between freezing and boiling of water is the same as the difference in deg C.

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