a 0.4 kg cube connected to a light spring for which the force constant is 20 N/m

Question

a 0.4 kg cube connected to a light spring for which the force constant is 20 N/m oscillates on a horizontal, frictionless track with an amplitude of 6 cm and a velocity of 4m/sec
what is the displacement?

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Need corrections on this questions Thanks SHOW ALL YOUR WORK 1. A 0.4 kg cube connected to a light spring for which the force constant is 20 N/m oscillates on a horizontal, frictionless track with an amplitude of 6 cm. and a velocity of 4 m/sec, what is the displacement 320 s(.oose 2) rl 2 .: x ,323 .57 m 57 m

Explanation / Answer

given

m = 0.4 kg

K = 20 N/m

A = 6 cm = 0.06 m

v = 4 m/s

Apply,

conservation of energy

0.5*k*A^2 = 0.5*k*x^2 + 0.5*m*v^2

0.5*k*x^2 = 0.5*k*A^2 - 0.5*m*v^2

x^2 = A^2 - (m/k)*v^2

x = sqrt(A^2 - (m/k)*v^2)

= sqrt(0.06^2 - (0.4/20)*4^2)

= sqrt(-0.3164)

so, the given data is not correct.

velocity may be 0.4 m/s

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