1. 12 pts] Consider two linked genes, a and b, in S.cereviia A spore with genoty
ID: 147425 • Letter: 1
Question
1. 12 pts] Consider two linked genes, a and b, in S.cereviia A spore with genotype a crossed with another spore with a genotype “+ b"-The fused cell mittically divided to generate 100 meiocytes. Each of the 100 meiocytes underwent meiosis. Among all the spores produced from these meiocytes, 20 had genotype "a b" (and the other spores had other genotypes). (a) 1 pt] Assume that no more than one crossover can occur per meiocyte. What is the percentage of the meiocytes that had a crossover between two genes? Briefly explain. b)ILpd] What is the map distance between two genes? Show your calculation.Explanation / Answer
Answer
It is given that 100 meiocytes underwent mieosis. One meiosis generates 4 cells hence 100 would generate 400 cell and out of 400, only 20 have 'a b' genotype which is nonparental genotype. This phenotype would be the result of crossing over resulting in recombination.
Hence remaining 380 are with parental type.
Hence percentage of recombinantion would be
% recombination =( 20/400)*100=5%
Hence percentage of recombinantion would be 5%
Map distance between the two gene is given by
The map distance = % of recombinantion =% of nonparental combination
= 5 m.u
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