Exercise 8.46 A 0.144 kg glider is moving to the right on a frictionless, horizo

Question

Exercise 8.46

A 0.144 kg glider is moving to the right on a frictionless, horizontal air track with a speed of 0.900 m/s . It has a head-on collision with a 0.293 kg glider that is moving to the left with a speed of 2.26 m/s . Suppose the collision is elastic.

Part A

Find the magnitude of the final velocity of the 0.144 kg glider.

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Part B

Find the direction of the final velocity of the 0.144 kg glider.

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Correct

Part C

Find the magnitude of the final velocity of the 0.293 kg glider.

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Part D

Exercise 8.46

A 0.144 kg glider is moving to the right on a frictionless, horizontal air track with a speed of 0.900 m/s . It has a head-on collision with a 0.293 kg glider that is moving to the left with a speed of 2.26 m/s . Suppose the collision is elastic.

Part A

Find the magnitude of the final velocity of the 0.144 kg glider.

m/s

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Incorrect; Try Again; 2 attempts remaining

Part B

Find the direction of the final velocity of the 0.144 kg glider.

to the right to the left

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Correct

Part C

Find the magnitude of the final velocity of the 0.293 kg glider.

m/s

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Part D

Explanation / Answer

initial momentum = 0.144kg * 0.900m/s - 0.293kg * 2.26m/s = -0.53 kg·m/s
final momentum = -0.53 kg·m/s = 0.144kg * u + 0.293 * v
For an elastic head-on collision, we know that the
relative velocity of approach = relative velocity of separation, or
0.90m/s - -2.26m/s = v - u
3.16 m/s + u = v
plug that into momentum eqn:
-0.53 = 0.144u + 0.293(3.16 + u) = 0.144u + 0.95 + 0.316u = 0.93 + 0.46u
u = -3.17m/s velocity of 0.144k g glider
The negative sign indicates "to the left".
v = 3.16 + u = -0.01 m/s velocity of 0.293kgkg glider
The negative sign indicates "to the left".

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