Calculate the (absolute) pressure at the bottom of a neighborhood swimming pool

Question

Calculate the (absolute) pressure at the bottom of a neighborhood swimming pool 26.0 m by 9 0 m whose uniform depth is 2.0 m pressure at the top of the pool is atmospheric pressure, which (in SI metric units) is 1 013 Times 10^5 Pa. Express your answer using two significant figures. Find the (total) force exerted on the bottom of this swimming pool. Express your answer using two significant figures. What is the pressure against the side of this pool (somewhere very near the bottom)? Express your answer using two significant figures.

Explanation / Answer

here,

area of pool , a = 26 * 9

a = 234 m^2

depth of water , d = 2 m

a)

the pressure at the bottom , P = Patm + p*g*h

P = 1.013*10^5 + 1000 * 9.8*2

P = 1.21 * 10^5 N/m^2

the pressure at the bottom of the swimming pool is 1.21 * 10^5 N/m^2

b)

the total force exerted on the bottom , F = P * area

F = 1.21 * 10^5 * 234

F = 2.83 * 10^7 N

the total force exerted on the bottom is 2.83 * 10^7 N

c)

the pressure against the side of the pool is same as bottom

i.e 1.21 * 10^5 N/m^2

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