A powerful 0.54-W laser emitting 670-nm photons shines on a black sail of a tiny
ID: 1475655 • Letter: A
Question
A powerful 0.54-W laser emitting 670-nm photons shines on a black sail of a tiny 0.10-g cart that can coast on a frictionless track.
Part A
Determine the force of the light on the sail. Assume that the light is totally absorbed by the sail.
Express your answer to two significant figures and include the appropriate units.
SubmitMy AnswersGive Up
Part B
What time interval is needed for the cart's speed to increase from zero to 2.0 m/s?
Express your answer using two significant figures.
SubmitMy AnswersGive Up
A powerful 0.54-W laser emitting 670-nm photons shines on a black sail of a tiny 0.10-g cart that can coast on a frictionless track.
Part A
Determine the force of the light on the sail. Assume that the light is totally absorbed by the sail.
Express your answer to two significant figures and include the appropriate units.
F =SubmitMy AnswersGive Up
Part B
What time interval is needed for the cart's speed to increase from zero to 2.0 m/s?
Express your answer using two significant figures.
t = sSubmitMy AnswersGive Up
Explanation / Answer
energy of the photons is E = h*c/lamda
h is planck's constant
c is speed of light
lamda is the wavelength of light
then E = (6.625*10^-34*3*10^8)/(670*10^-9) = 2.96*10^-19 J
but this is completely absobed by the sail to move
hence E = 0.5*m*v^2 = 0.5*0.1*10^-3*v^2 = 2.96*10^-19
v = 7.69*10^-8 m/s
then we know that Power P = F*v
then Force F = P/v = 0.54/(7.69*10^-8) = 7.01*10^6 N
----------------------------------------------------------
B) P = W/t
but W = change in kinetic energy = 0.5*m*v^2 = 0.5*0.1*10^-3*2*2 = 0.2*10^-3 J
time t = W/P = 0.2*10^-3 / 0.54 = 0.37*10^-3 S = 0.37 milli S
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.