A 0.5970-kg ice cube at -12.40 degreeC is placed inside a chamber of steam at 36

Question

A 0.5970-kg ice cube at -12.40 degreeC is placed inside a chamber of steam at 365.0 degree C. Later, you notice that the ice cube has completely melted into a puddle of water. If the chamber initially contained 5.830 moles of steam (water) molecules before the ice is added, calculate the final temperature of the puddle once it settled to equilibrium. (Assume the chamber walls are sufficiently flexible to allow the system to remain isobaric and consider thermal losses/gains from the chamber walls as negligible.)

Explanation / Answer

The mass of the steam is

The mass of ice is 0.6190 kg.

At thermal equilibrium,

Solve the above equation with any equation solver tool. While solving use the following simplified equation.

(0.1114)(1996)(365-100)+(0.1114)(2270*10^(3))+(0.1114)(4187)(100-T)= (0.619)(2108)(12.4) + (0.619)(334*10^(3)) + (0.6190)(4187)T

The required temperature is,

           

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