Rn=0.21 cm Rh=0.89 cm Q= 0.45 L/s A) Calculate the maximum height to which water

Question

Rn=0.21 cm Rh=0.89 cm Q= 0.45 L/s A) Calculate the maximum height to which water could be squirted with the hose if it emerges from the nozzle in M.
ust44tn. Date and T How German higher edu ail- Vaughn, Kaleb o OWLY2 | Online teachin... The Expert TA / Human-I Home I uids Begin Date: 11/11/2015 12:00:00 AM-Due Date: 12/11/2015 12:00:00 AM End Date: 12/11/2015 12:00:00 AM a3% ) Problem 7: Anode with a radius of 0.21 hose and nozzle is 0.45 L/s Problem 7: A nozzle with a radius of 0,21 cm is attached to a garden hose with a nadius of 0.39 cm. The Row rate through msattached to a garden hoe wit ara sofona Randomized Variables r.-0.21 ,h = 0.89 0-045 LUs > 50% Part (a) Calculate the maximum height to which water could be s in d ith the osert emerges from the onl n h2 = Deductions cotanO asin acos atan acota) sinho cosh tanh cotanho per anemp) O Degrees Radians sunta: 0% dedactionper hint Hits remaining: with the how ritenerges w th the tider on 50% Part (b) Calculate the maximum height (in cm) to which waer could be squirted assuming the same flow rate . 8 0 0

Explanation / Answer

A) Let vn is the speed of water through the nozzle

we know, volume flow rate = An*vn

0.45 L/s = pi*Rn^2*vn

0.45**10^-3 m^3/s = pi*0.0021^2*vn

==> vn = 0.45*10^-3/(pi*0.0021^2)

= 32.5 m/s

so, maximum height reached, Hn = vn^2/(2*g)

= 32.5^2/(2*9.8)

= 53.4 m <<<<<<<----------Answer

B) now Apply continuty equation

Ah*Vh = An*vn

pi*Rh^2*vh = pi*Rn^2*vn

vh = (Rn/Rh)^2*vn

= (0.21/0.89)^2*32.5

= 1.81 m/s

maximum height reached, Hh = vh^2/(2*g)

= 1.81^2/(2*9.8)

= 0.167 m <<<<<<<----------Answer

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