The triple point of water is chosen as the fixed point and is defined at 273.16K
ID: 1476971 • Letter: T
Question
The triple point of water is chosen as the fixed point and is defined at 273.16K. The absolute zero is 0K, the ice point is 273.15K and the steam point is 373.15K. If P is the temperature measuring quantity such as gas pressure at constant volume or electrical resistance of a pure metal, if P_tr is value of P at triple point and P_T is the value at an unknown temperature T on the absolute thermodynamic scale Then, T= (P_T/P_tr) Times (273.16) If P is the chosen temperature-measuring quantity, its value P_0 at the ice point and P_100 at the steam point determine the fundamental interval, 100 degree C, of the Celsius scale, P_100 - P_0. And the temperature theta_P on the Celsius scale which is theta_p = (P_theta - P_0)/(P_100 - P_0) times (100) Question: The pressure recorded by a constant volume gas thermometer at a Kelvin temperature T is 4.80 Times 10^4 Nm^-2. Calculate T if the pressure at the triple point, 273.16 K is 4.20 Times 10^4 Nm^-2.Explanation / Answer
Given :-
Pressure at thermometer = 4.80 × 10^4 N/m^2
Pressure at triple point = 4.20 × 10^4 N/m^2
T0 = 273.16 k
T = ( Pt/Ptr )*(273.16 )
T = ( 4.20 × 10^4/4.80 × 10^4)*(273.16)
T = 239.015 k
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