As part of an honors project, a student wishes to construct a series of lenses w
ID: 1477206 • Letter: A
Question
As part of an honors project, a student wishes to construct a series of lenses with different focal lengths. Not having glass grinding equipment, the student makes a series of lenses by partially filling cylindrical containers with water (n = 4/3). For the container to the right with radius 4.0cm, what is the focal length of the lens? Ignore the glass of the container and assume a thin lens. You do not need to know the thickness of the water to complete the problem. You are playing a game where you drop a coin into a water tank and try to land it on a target. You often find this game at fast food places as part of a fundraiser. The sides of the tank are flat and the target is Gin from the side of the tank. Your eye is 9in from the side of the tank Water has index of refraction of 4/3. If you drop the coin accurately and it falls straight down to the location where the target appears to be, how far are you off? Does the coin fall in front or behind the target as you look at it? The power output of the son is 3.846 times 10^26W and the radius of the sun (approximately) is 6.96 x 10^8m. Calculate the total force at normal incidence on a perfectly reflecting circular mirror of area lm^2 placed at the sun's surface (before it vaporizes). If an artificial ruby (n = 1.7) was formed into a double convex lens with radii of magnitude 50 cm and 75cm, what would the focal length of the lens be? Note, you will have to determine the signs of the radii.Explanation / Answer
from lens makers equation
1/f = (n-1)*(1/R1 - 1/R2)
R1 = +4
R2 = infinity
1/f = (4/3-1)*(1/4-0)
f = 12 cm
option d
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object distance = s = 6 in
image distance = s'
for plane refraction
n1/s + n2/s' = 0
(4/3)/6 + 1/s' = 0
s' = -4.5 in
the image appears at 4.5 in from hte side of the tank
the image is 6-4.5 = 1.5 in infront of the target
option d
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intensity S = P/(pi*R^2)
force = (S*A)/c
F = (P*A)/(pi*R^2*c)
F = (3.846*10^26*1)/(pi*(6.96*10^8)^2*3*10^8)
F = 0.84 N
option (b)
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