Item 15 You pull a simple pendulum of length 0.215 m to the side through an angl

Question

Item 15
You pull a simple pendulum of length 0.215 m to the side through an angle of 3.50 and release it.
Part A
How much time does it take the pendulum bob to reach its highest speed?
Take free fall acceleration to be 9.80 m/s2 .

t=
s

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Part B
How much time does it take if the pendulum is released at an angle of 1.75instead of 3.50?

t=
s

Item 11
A 2.90 kg mass on a spring has displacement as a function of time given by the equation
x(t)=(7.40cm)cos[(4.16rad/s)t2.42rad].

Part E
Find the position of the mass at t=1.00s;

x=
m

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Part F
Find the speed of the mass at t=1.00s;

v=
m/s

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Part G
Find the magnitude of acceleration of the mass at t=1.00s;

a=
m/s2

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Part H
Find the magnitude of force on the mass at t=1.00s;

F=
N

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Explanation / Answer

only 1 question at a time please
Q 15)
A)
for small angle:
T = 2*pi* sqrt (L/g)
=2*3.14*sqrt (0.215/9.8)
=0.93 s
It is not dependent of any angle
It will be at its maximum height at T/2
Answer: 0.93/2 = 0.47 s
B)
Time is independent of angle.
So answer will be same
Answer: 0.47 s

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