if a fulcrum is placed at the 30 cm mark on a meter stick and a 240 g mass must

Question

if a fulcrum is placed at the 30 cm mark on a meter stick and a 240 g mass must be placed at the 15cm mark on the meter stick to balance it, what is the mass of the meter stick? assume uniform density of the stick if a fulcrum is placed at the 30 cm mark on a meter stick and a 240 g mass must be placed at the 15cm mark on the meter stick to balance it, what is the mass of the meter stick? assume uniform density of the stick if a fulcrum is placed at the 30 cm mark on a meter stick and a 240 g mass must be placed at the 15cm mark on the meter stick to balance it, what is the mass of the meter stick? assume uniform density of the stick

Explanation / Answer

Given it is a meter stick, so center of mass is located at 50 cm.

Now a fulcrum is placed at the 30 cm mark on a meter stick and a 240 g mass must be placed at the 15cm mark on the meter stick to balance it.

Let the mass of stick be M kg

For equilibrium about 30cm mark, we write

Mg(50-30) =mg(30-15)

M = 15*240gm/20 = 180 grams

M= 0.180 Kg

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