A 1.50 m long ramp is inclined at 17 to the horizontal. A solid ball is released
ID: 1479004 • Letter: A
Question
A 1.50 m long ramp is inclined at 17 to the horizontal. A solid ball is released from rest at the top of the ramp.
Part A
Find the ball's speed at the bottom of the ramp.
Express your answer with the appropriate units.
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Part B
Find its translational acceleration.
Express your answer with the appropriate units.
A 1.50 m long ramp is inclined at 17 to the horizontal. A solid ball is released from rest at the top of the ramp.
Part A
Find the ball's speed at the bottom of the ramp.
Express your answer with the appropriate units.
v =SubmitMy AnswersGive Up
Part B
Find its translational acceleration.
Express your answer with the appropriate units.
a =Explanation / Answer
a)
vertical distance travelled, h = 1.5*sin(17)
= 0.438 m
let v is the speed of ball at bottom,
Apply conservation of energy
final kinetic energy = initial potentail energy
0.5*m*v^2 + 0.5*I*w^2 = m*g*h
0.5*m*v^2 + 0.5*(2.5)*m*r^2*w^2 = m*g*h
0.5*m*v^2 + 0.2*m*(r^2*w^2) = m*g*h
0.5*m*v^2 + 0.2*m*v^2 = m*g*h
0.7*m*v^2 = m*g*h
v = sqrt(g*h/0.7)
= sqrt(9.8*0.438/0.7)
= 2.48 m/s <<<<<------------------Answer
B) let a is the acceleration of the ball.
Apply, v^2 - u^2 = 2*a*s
==> a = (v^2 - u^2)/(a*s)
= (2.48^2 - 0^2)/(2*1.5)
= 2.07 m/s^2 <<<<<------------------Answer
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