9:47 PM 58% LD iPad D Current Services x D A VA www.webassign.n x Welcome to Bec

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9:47 PM 58% LD iPad D Current Services x D A VA www.webassign.n x Welcome to Beck X eCampus C D www.webassign.net Response /web/Student/Assignment order to determine the frequency of Oscillation for the new longer rope? Hz 0.785 0.858 distance How is the force constant for the new longer rope related to the force constant for the shorter rope? Can you stretched find a way to modify your expression for the stretch of the shorter rope from part (b) in order to determine the stretch for the new longer rope? m Supporting Materials Physical Constants Additional Materials Reading New Randomization -1 points OSColPhys 6.P. 020 WA. 0/6 Submissions Used My Notes A mass is attached to the end of a spring and set into oscillation on a horizontal frictionless surface by releasing it from a stretched position. The position of the mass at any time is described by x 8.0 cm)cos 3.08 s)]. Determine the following (a) period of the motion (b) frequency of the oscillations Hz (c) first time the mass is at the position X (d) first time the mass is at the site of maximum compression of the spring Supporting Materials Physical Constants Additional Materials Reading 6. 1/1 points l Previous Answers oscolPhys1 16.P.032.WA. 1/6 submissions used My Notes When a pendulum with a period of 2.00000 s is moved to a new location from one where the acceleration due to gravity was 9.80 m/s its new period becomes 1.99770 s. By how much does the acceleration due to gravity differ at its new location? 0.02258 m/s2 Supporting Materials Physical Constants

Explanation / Answer

here,

x = (8 cm) * cos( (2*pi/3.08) * t )

(a)

the angular speed , w = 2*pi/3.08

time periodd , T= 2*pi/w

T = 2*pi /( 2*pi/3.08)

T = 3.08 s

the period is 3.08 s

(b)

frequency , f = 1/T

f = 1/3.08

f = 0.32 Hz

the frequency is 0.32 Hz

(c)

when x = 0 ,

0 = (8 cm) * cos( (2*pi/3.08) * t )

t = 0.77 s

the time is 0.77 s

(d)

initially the mass is at the streched position

so at t = 0 , the the mass is at the site of teh maximum compression and afetr that

at t = 1.54 s , it is at the maximum position of compression

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