Water enters a horizontal pipe with a rectangular cross section at a speed of 1.

Question

Water enters a horizontal pipe with a rectangular cross section at a speed of 1.00 m/s. The width of the pipe remains constant but the height decreases. 50 m from the entrance, the height is half of what it is at the entrance. If the water pressure at the entrance ism4600 Pa, what is the pressure 50.0 m downstream?

Water enters a horizontal pipe with a rectangular cross section at a speed of 1.00 m/s. The width of the pipe remains constant but the height decreases. Fifty meters from the entrance, the height is half of what it is at the entrance. If the water pressure at the entrance i600. Pa, what is the pressure50.0 m downstream? Pa

Explanation / Answer

half the area is twice the speed

V1 = 1 m/s

V2 = 2 m/s

Bernoulli

(1/2) rho V1^2+P1 = (1/2) rho V2^2+P2

rho water =1000 kg/m^3

4600 Pa is very low by the way, like 1 atm = 100,000 Pa for example. Perhaps they mean gauge pressure.

500 (1)^2 + 4600 = 500 (2)^2 + P2

P2=3100Pa

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