Two very large parallel sheets are 5.00 cm apart. Sheet A carries a uniform surf
ID: 1479712 • Letter: T
Question
Two very large parallel sheets are 5.00 cm apart. Sheet A carries a uniform surface charge density of -8.80 C/m2 , and sheet B, which is to the right of A, carries a uniform charge of -11.9 C/m2 . Assume the sheets are large enough to be treated as infinite.
Part a.
Find the magnitude of the net electric field these sheets produce at a point 4.00 cm to the right of sheet A.
Part B
Find the direction of the net electric field these sheets produce at a point 4.00 cm to the right of sheet A.
Part C
Find the magnitude of the net electric field these sheets produce at a point 4.00 cm to the left of sheet A.
Part D
Find the direction of the net electric field these sheets produce at a point 4.00 cm to the left of sheet A.
Part E
Find the magnitude of the net electric field these sheets produce at a point 4.00 cm to the right of sheet B.
Part F
Find the direction of the net electric field these sheets produce at a point 4.00 cm to the right of sheet B.
Explanation / Answer
electric field due to infinite sheet of charge = linear charge density / e0
the magnitude of the net electric field these sheets produce at a point 4.00 cm to the right of sheet A = electric field due to A - electric field due to B
because direction of electric field are opposite
the magnitude of the net electric field these sheets produce at a point 4.00 cm to the right of sheet A = -8.8 * 10^-6 / e0 - (-11.9 * 10^-6 / e0)
the magnitude of the net electric field these sheets produce at a point 4.00 cm to the right of sheet A = 3.1 * 10^-6 / (8.85 * 10^-12)
the magnitude of the net electric field these sheets produce at a point 4.00 cm to the right of sheet A = 350282.485 N/C
direction will be toward sheet B
magnitude of the net electric field these sheets produce at a point 4.00 cm to the left of sheet A = electric field due to A + electric field due to B
because direction of electric field are same
the magnitude of the net electric field these sheets produce at a point 4.00 cm to the left of sheet A = -8.8 * 10^-6 / e0 + (-11.9 * 10^-6 / e0)
the magnitude of the net electric field these sheets produce at a point 4.00 cm to the left of sheet A = -20.7 * 10^-6 / (8.85 * 10^-12)
the magnitude of the net electric field these sheets produce at a point 4.00 cm to the left of sheet A = -2338983.05 N/C
direction will be toward sheet A
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