Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

With reference to the metabolic pathways involved, explain your observations of

ID: 147978 • Letter: W

Question

With reference to the metabolic pathways involved, explain your observations of glucose concentration across the strains under the different conditions:

Keep it brief if possible, thanks (only a breif summary need to be included , no super intense detail, Cheers

Concentration of Extracellular Glucose in growth medium Growth time of cultures Cell concentration cells/mL rowth (Tm 3.75 mM No. Carbon O2 Strain of EtOH Presence at cessation of Initial (To)Final (Tm) source 30 1Glucose 8.450 0.022 0 20 Yes 0.35 8.399 0.017 20 2 Glucose Yes 0.55 8.637 0.0189 20 Yes 0.5 8.688 0.0183 30 Pyruvate 5.2 NIA NIA 0 NIA NIA NIA 0

Explanation / Answer

From row 1

There's sufficient O2 and both the strains are utilizing most of the glucose provided to them to divide (the increase in cell concentration). The Pe strain is probably not very metabolically active due to low conc. of cells and production of EtOH whereas Gr strain is not producing EtOH. This shows that Gr strain is using Os for glycolysis and subsequent oxidation of pyruvate.

From row 2

Now there's no O2. Gr strain is again utilizing most of the glucose but it is not metabolically feasible because the cell conc. isn't much. In case of Pe strain, there's no difference compared to the earlier case where we had O2 so we can say that the Pe strain is insensitive to O2 and utilizes Glucose. EtOH is produced by the Gr strain due to lack of oxygen.

From row 3

Gr strain in the presence of O2 and pyruvate continues the process whereas the Pe strain cannot use pyruvate to harvest energy from it.

To conclude, Ge strain is undergoing normal Glycolysis and oxidation of pyruvate molecule and can use Glucose and Pyruvate as a carbon source. The Pe strain, on the other hand, is producing energy anaerobically and can only utilize glucose as a carbon source and not pyruvate.
If this answer was helpful then please give it a good rating, Thank You.

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote