As part of a carnival game, a 0.578-kg ball is thrown at a stack of 21.8-cm tall

Question

As part of a carnival game, a 0.578-kg ball is thrown at a stack of 21.8-cm tall, 0.383-kg objects and hits with a perfectly horizontal velocity of 12.8 m/s. Suppose the ball strikes the topmost object as shown to the right. Immediately after the collision, the ball has a horizontal velocity of 4.60 m/s in the same direction, the topmost object now has an angular velocity of 5.23 rad/s about its center of mass and all the objects below are undisturbed. If the object's center of mass is located 15.3 cm below the point where the ball hits, what is the moment of inertia of the object about its center of mass? What is the center of mass velocity of the tall object immediately after it is struck?

Explanation / Answer

the solution for this question is

moment of inertia

0.578 * 12.8 * (15.3 / 100) = 0.578 * 4.6 * (15.3 / 100) + I * 5.23

by solving this equation we get I

I = 0.1386 kg*m^2

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