https//session.masteringphysics.com/myct/itemView?assi MP2054.Fall15 chapter 24

Question

https//session.masteringphysics.com/myct/itemView?assi MP2054.Fall15 chapter 24 Problem 24.50 set- = next art Problem 24.50 the image position. Enter your answer as two numbers separated with a comma A diverging lens has a focal length of 13.5 cm For each of two objects located to the left of the lens one at a distance of s1 21.5 cm and the other at a distance of s2 = 3 00 cm , determine cm Submit My Answers Give Up Part B the magnification Enter your answer as two numbers separated with a comma. cm

Explanation / Answer

Given that

The focal length of thediverging lens (f) =-13.5cm

Now from the equation we know that

1/f =1/v+1/u

1/v =1/f-1/u

v =(-13.5*21.5)/(21.5+13.5) =-8.292cm or s1' =-8.292cm

then the magnification is m1 =-v/u =8.292/21.5 =0.3856

Now for the second object distance the image distance is given by

v =(3.00)(-13.5)/(13.5+3) =-2.4545cm or s2' =-2.4545cm

the magnification m2 =-v/u =2.4545/3 =0.8181

The total magnification is given by M =0.8181*0.3856=0.3154

c)

Both the images are virtual

d)

and both the iamges are eract

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