Two equal masses, M1=10 Kg and M2=10 Kg, are connected over an ideal pulley as s

Question

Two equal masses, M1=10 Kg and M2=10 Kg, are connected over an ideal pulley as shown in the diagram. The horizontal surface has a coefficient of kinetic friction Uk=0.5. If they start from rest with d=3 m, how long a time t will it take for M2 to strike the ground?

***the answer from this picture is A) 1.55 s ***Gravity (g) is 10.0, Not 9.8 for this answer (per teacher's request)

2) [HI Two equal masses, Mi-10 Kg and M-10 Kg, M are connected over an ideal pulley as shown in the diagram. The horizontal surface has a coefficient of! kinetic friction k=05. If they start from rest with d=3 m, how long a time t will it take for M, to strike the ground? Answer A) 1.55 s B) 1.75 s C 1.95 s D) 2.15 s E) 2.35 s 3) M You're driving yourt car through your

Explanation / Answer

here,

M1 = 10 kg

M2 = 10 kg

uk = 0.5

d = 3 m

the accelration of the system , a = net force /( effective mass)

a = ( M2*g - uk*M1*g ) /( M1 + M2)

a = ( 10 * 10 - 0.5 * 10 *10 )/( 10 +10)

a = 2.5 m/s^2

let the time taken be t

d = u*t + 0.5 * a*t^2

3 = 0 + 0.5 * 2.5 * t^2

t = 1.55 s

the time taken is A) 1.55 s

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