In the figure, the B field (out of the page) is 2.75 T, the speed of the loop is

Question

In the figure, the B field (out of the page) is 2.75 T, the speed of the loop is v = 5.20 m/s (in the direction shown), the length of one side of the loop is L = 30.0 cm and the resistance in the resistor is R = 100 ?.

a. Find the current (magnitude and direction) in the loop as the wire enters the region of the B field.

b. What id the power dissipated in the resistor while the loop is entering the field?

c. Find the current (magnitude and direction) in the loop when it is completely within the B field.

d. Find the current (magnitude and direction) in the loop when as the wire leaves the region of the B field.

Explanation / Answer

a) Indued emf = B*v*L

induced current = induced emf/R

= B*v*L/R

= 2.75*5.2*0.3/100

= 0.0429 A

dirction : clockwise

b) Power sissipated, P = I^2*R

= 0.0429^2*100

= 0.184 W

c) zero.Because there is no chnage in megnatic flux through the loop.

d) Indued emf = B*v*L

induced current = induced emf/R

= B*v*L/R

= 2.75*5.2*0.3/100

= 0.0429 A

dirction : counter-clockwise

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