6kg of water at 30C is added to a large quantity of ice at 0C resulting in ice-w

Question

6kg of water at 30C is added to a large quantity of ice at 0C resulting in ice-water. How much water (looking for mass) is there in the final state? What is the total change in entropy in this process? 6kg of water at 30C is added to a large quantity of ice at 0C resulting in ice-water. How much water (looking for mass) is there in the final state? What is the total change in entropy in this process? 6kg of water at 30C is added to a large quantity of ice at 0C resulting in ice-water. How much water (looking for mass) is there in the final state? What is the total change in entropy in this process?

Explanation / Answer

Q = m*c*delta T

heat loss = 6*4186*30 = 753480 J

let mass of ice = m

The latent heat of fusion = 334*103 J/kg

so m*334*103 J/kg = 753480 J

m = 2.255 kg

delta S = Q/T = 753480/273 = 2760 J/K

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