Object A, mass 3.64×10 5 kg , is at rest in reference frame A, and object B, mas

Question

Object A, mass 3.64×105 kg , is at rest in reference frame A, and object B, mass 5.71×104 kg , moves at 0.875 c0 in the positive xdirection in this reference frame. A reference frame C moves at 0.400 c0 relative to reference frame A and moves in the same direction as object B.

What does an observer at rest in A measure for the momentum of B?

What does an observer at rest with respect to object B measure for the momentum of A?

What is the momentum of the object A as measured by an observer at rest in reference frame C?

What is the momentum of the object B as measured by an observer at rest in reference frame C?

Explanation / Answer

1) momentum M = m*v = 5.71*10^4 * 0.875

= 49962.5 Kg*c0.

2) the observer is at rest with respect to object B, it implies that the observer is also moving with the same velocity as object B. So to this observer the object A will move with a velocity of v = 0.875 c0 in the opposite direction as object B.

So momentum of A with respect to that observer = m*v

= 3.64×10^5 * 0.875

= 318500 Kg*c0.

3) the momentum of object A = mass of A * velocity of reference frame C

= 3.64×10^5 * 0.400

= 145600 Kg*c0.

4) momentum of object B with respect to reference frame C = mass of B * velocity of object B with respect to C.

= mass of B * [velocity of B - velocit of reference frame C]

= 5.71×10^4 * [0.875 - 0.400]

= 5.71×10^4 * 0.475

= 27122.5 kg*c0.

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