13[H]) You take a rectangular conductor of width 4 cm and length 8 cm and move i

Question

13[H]) You take a rectangular conductor of width 4 cm and length 8 cm and move it with a steady speed of 9 cm/s lengthwise through a uniform magnetic field of strength 4 T directed perpendicularly to both the length and width of the conductor. You reason that since the conductor has free electrons that are moving through the magnetic field, they will be pushed by a magnetic force which ought to lead to polarization, and thus, an electric field within the conductor that counteracts the force exerted by the magnetic field. How strong does this electric field need to be to reestablish equilibrium within the conductor?

Answer:  

14[M]) What is the voltage difference between the negative and positive sides of the conductor?

Answer:  

15[M]) Consider the following setup: You connect the rectangular conductor to a track consisting of two very good conducting rails on either end. At the far end of the track is a wire with a resistance of 50 Ohm that connects to the two conducting rails. By sliding the rectangular conductor in the same manner as you were earlier, can you get a current to flow around the rails and the wire? If not, enter 0 A as your answer. If yes, enter the amount of current as your answer.

(PLEASE INCLUDE UNITS)

Explanation / Answer

when a conducting rod is moving in magnetic field

e = B*v*L

E = e/L = B*v

E = 4*0.09

E = 0.36 V/m

++++++++++

i = e/R = E*L/R = 0.36*0.08/50

i = 0.00058 A

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