1) An infinitely long wire is bent 90o at the coordinate origin. One leg of the

Question

1) An infinitely long wire is bent 90o at the coordinate origin. One leg of the bent wire is along ax with the current direction towards the origin. The 2nd leg is along ay with the current direction away from the origin, both wires are in the xy-plane, z=0. If the wire carries a current of 10 A, calculate the following: a) H at (0, 0, 2m) b) H at (3m, 3m, 0) NOTE: BOTH components MUST be referenced to a common coordinate system and clearly show the H components from each wire segment for partial credit !!

Explanation / Answer

at (0,0,3)

H due to ax is Hx = mu_o*i/(2*pi*r) = 2*10^-7*10/2 = 10^-6 T

H due to ay is Hy = (mu_o*i)/(2*pi*r)= 10^-6 T

but both Hx and Hy are perpendicular to each other

H = sqrt(Hx^2+Hy^2) = sqrt(2)*Hx = 1.414*10^-6 T

B) (3m,3m,0)

Hx = mu_o*i/(2*pi*r) = (2*10^-7*10)/(3) = 0.667*10^-6 T

Hy = 0.667 *10^-6 T

Hx and Hy are in same direction

H = Hx+Hy = 1.3*10^-6 T along -Z axis

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.