When the block is launched, it gets through the frictional part, rises up the ra

Question

When the block is launched, it gets through the frictional part, rises up the ramp to point D, a height h above the straight part of the ramp. It then slides back down. On its return, it gets to point B and stops. The distances are shown on the figure, and the angle of the ramp is as shown. Given the following values for the parameters, can you calculate the value of the coefficient of friction, ? If you can, put the value in the box and explain how you got it. If not, explain why not and what information would allow you to calculate it. m = 75 g k = 15 N/m d1 = 10 cm d2 = 10 cm d3 = 8 cm L = 25 cm = 20o If you need the earth's gravitational field, use the approximate value g = 10 N/kg.
= __________

Explanation / Answer

Consider the return journey of blocke From E to B

At E the energy of block is mg h

at B its energy is zero

from work energy theorem

mgh+ work done by friction = zero

mgh - u mg L = zero

u = h/L

from triangle h / d3 = tan theta h = d3 tan theta

= 8 tan20 /25

= 0.116 ( answer)

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