A man lifts one end of a wheelbarrow with a vertical force, F, and holds it stat

Question

A man lifts one end of a wheelbarrow with a vertical force, F, and holds it stationary. The horizontal distances from where he hold the handle to the center of mass of the wheelbarrow and to the point where the wheel touches the ground are shown in the figure below. If the mass of the wheelbarrow is 65 kg, what is the magnitude of the force, F?

Please show work and explain, Thanks!

E 522 N A man lifts one end of a wheelbarrow with a vertical force, F, and holds it stationary. The horizontal distances from where he holds the handle to the center of mass of the wheelbarrow and to the point where the wheel touches the ground are shown in the figure below. If the mass of the wheelbarrow is 65 kg, what is the magnitude of the force, F? 65 F- 63 to 0.9 m ,3 1.2 m A 159 N B 1115 N C 478 N D 637 N E 319 N G51

Explanation / Answer

net torque is zero because man holds it in stationary

F1*r1 = F2*r1

mg * 0.9 = F2 * 1.2

F2 = 65 * 9.8 * 0.9 /1.2

F2 = 478 N

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