1-Two point charges q, and q, are a distance r apart Write the law to find the f

Question

1-Two point charges q, and q, are a distance r apart Write the law to find the force between them. (Use k for 2- If the previous result is Fi then when the charges are separated 4r from ea each other the result would be e) 16. Fu a)F2 /4 b) F1a/8 c) F/16 d) 4.Fu C attracts charge D What is the force between repulsion? A and D, attraction or 4-Write the formula to calculate the electric potential energy of the two charge system of Prob. 1 above 5-Call the previous result Ug Now, if the two charges are separated Ar, what would be the new potential energy? a)Un 14 e) 16. Ua 6-If the two charges of Prob. 1 have opposite signs a)the mutual force Fa would be attractive or repuisive? b) the potential energy Uz would be positive or negative?

Explanation / Answer

1)

colulomb's law of electrostatics :

the electric force between the two charges is directly proportional to product of magnitudes of charges and inversely proportioanl to square of the distance between their centers

F12 = k*q1*q2/r^2

==============

2)

if r becomes 4r

then F = k*q1*q2/(4r)^2 = k*q1*q2/16r^2

F = F12/16

option (c)

+++++++++

3)

A = +q1

B = -q2

C = +q3

D = -q4

A & D opposite signs

A&D attract each other

answer : attraction

++++++

4)

U12 = k*q1*q2/r

+++++++++

5)

U = k*q1*q2/4r = U12/r

option (a)

+++++++

6)

(a)

attraction

(b)

negative

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.