A variable dielectric capacitive displacement sensor consists of two square meta

Question

A variable dielectric capacitive displacement sensor consists of two square metal plates of side 5 cm, separated by a gap of 1 mm. A sheet of dielectric material 1 mm thick and of the same area as the plates can be slid between them as shown in the figure. Given that the dielectric constant of air is 1 and that of the dielectric material 4mm, calculate the capacitance of the sensor when the input displacement x = 0.0, 2.5 and 5.0 cm.

Equivalent to C1 // C2 CT= C1 + C2 Variable dielectric Since Al = WX, A.-w(1-x), when w is the width of the plates. d=1mm W=50mm l=50mm -854x10-12 (F/m) e)W C =-[6/-(e,-8)

Explanation / Answer

Just put the values of x into given formula to calculate capacitance.as all the parameters are given.

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