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York College Phys-117YY Quiz#1 4 Name Oil flows through a constricted pipe in st

ID: 1486770 • Letter: Y

Question

York College Phys-117YY Quiz#1 4 Name Oil flows through a constricted pipe in steady state In the larger section the diameter is 12.00cm and the speed is 0.012m/s. The pipe rises through a height of 12.00m and the diameter of the pipe at that height is 1.00cm. The oil is collected in a container at a higher point. The pressure at the higher point is 1.013X10 Pa. The density of the oil is 750.00kg/m', 1.000L = 1000cm" a) What is the pressure in the larger section? b) How long will it take to fill a container of 30.00L with oil?

Explanation / Answer

d1 =12 cm , r1 =6 cm

v1 =0.012 m/s, h1 =0 ,h2 = 12m , d2 =1cm , P2 =1.013x10^5 Pa

denisty of oil d = 750 kg/m^3, 1 L =1000cm^3

a) Volume flow rate is constant

A1v1 =A2v2

v2 = (A1/A2)v1 = (d1/d2)^2 v1

v2 = (12/1)^2 (0.012)

v2 = 0.288 m/s

From Bernoullis theorem

P1+(1/2)dv1^2 +dgh1 = P2+(1/2)dv2^2 +dgh2

P1 +((1/2)750*0.012*0.012) = 101300 +((1/2)750*0.288*0.288) +(750*9.8*12)

P1 = 189531 Pa

b) Volume =30 L = 30*0.001 = 0.03 m^3

Volume flow rate V/t = Av

t = V/A1v1 = (0.03)/(3.14*0.06*0.06*0.012)

t =221.16 s

t =221.16 =3.686 min