A branch of a tree grows out from the trunk at an angle of 27.5 degree above the
ID: 1487024 • Letter: A
Question
A branch of a tree grows out from the trunk at an angle of 27.5 degree above the horizontal. Two children hang by their hands from the branch of the tree. The first child has a mass of 42.0 kg and hangs 1.45 m from the tree trunk, as measured along the length of the branch. The second child, with a mass of 30.0 kg, hangs 1.80 m from the tree trunk, also measured along the branch. Determine the magnitude of the net torque exerted on the branch by the children, about an axis located where the branch joins the tree trunk and is perpendicular to the plane formed by the branch and the trunk.Explanation / Answer
m1 = 41.0 kg d1 = 1.25 m m2 = 30.0 kg d2 = 2.20 m Net torque = m1 * g * d1 cos(27 deg) + m2 * g * d2 cos(27 deg) = 41 x 9.8 x 1.25x cos(27 deg) + 30 x 9.8 x 2.20 x cos(27 deg) = 1023.81 N.m
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