Problem 25.18 Object A, which has been charged to + 4.4 nC , is at the origin. O
ID: 1487287 • Letter: P
Question
Problem 25.18
Object A, which has been charged to + 4.4 nC , is at the origin. Object B, which has been charged to 7.8 nC , is at (x,y)=(0.0cm, 1.8 cm ).
Part A
What is the x-component of the force (F AonB)x on B due to A?
Express your answer to two significant figures and include the appropriate units.
0 N
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Correct
Part B
What is the y-component of the force (F AonB)y on B due to A?
Express your answer to two significant figures and include the appropriate units.
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Part C
What is the x-component of the force (F BonA)x on A due to B?
Express your answer to two significant figures and include the appropriate units.
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Part D
What is the y-component of the force (F BonA)y on A due to B?
Express your answer to two significant figures and include the appropriate units.
(F AonB)x =0 N
Explanation / Answer
electrostatic force = kq1q2/r^2
r = separation b/e charges = 1.8 cm = (1.8/100) m
9*10^9 * (10^(-18))* 4.4*7.8/((1.8/100))^2
= 0.00095333333 N
since they are of opposite nature so they will attaract each other
x-component of the force on B due to A = 0
y-component of the force on B due to A = -0.00095333333 N
-ve sign is due to the fact that A particle attaracts B in downward direction i.e. force in -ve y direction
x-component of the force on A due to B = 0 N
y-component of the force on A due to B = 0.00095333333 N
by newton's third law of motion they will exert same magnitude of force on each other in opposite directions
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