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Problem 25.18 Object A, which has been charged to + 4.4 nC , is at the origin. O

ID: 1487287 • Letter: P

Question

Problem 25.18

Object A, which has been charged to + 4.4 nC , is at the origin. Object B, which has been charged to 7.8 nC , is at (x,y)=(0.0cm, 1.8 cm ).

Part A

What is the x-component of the force (F AonB)x on B due to A?

Express your answer to two significant figures and include the appropriate units.

0 N

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Correct

Part B

What is the y-component of the force (F AonB)y on B due to A?

Express your answer to two significant figures and include the appropriate units.

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Incorrect; Try Again; 2 attempts remaining

Part C

What is the x-component of the force (F BonA)x on A due to B?

Express your answer to two significant figures and include the appropriate units.

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Incorrect; Try Again; 4 attempts remaining

Part D

What is the y-component of the force (F BonA)y on A due to B?

Express your answer to two significant figures and include the appropriate units.

(F AonB)x =

0 N

Explanation / Answer

electrostatic force = kq1q2/r^2

r = separation b/e charges = 1.8 cm = (1.8/100) m

9*10^9 * (10^(-18))* 4.4*7.8/((1.8/100))^2

= 0.00095333333 N

since they are of opposite nature so they will attaract each other

x-component of the force on B due to A = 0

y-component of the force on B due to A = -0.00095333333 N

-ve sign is due to the fact that A particle attaracts B in downward direction i.e. force in -ve y direction

x-component of the force on A due to B = 0 N

y-component of the force on A due to B = 0.00095333333 N

by newton's third law of motion they will exert same magnitude of force on each other in opposite directions

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