1) A rubber stopper with a mass of 26 g (.026 kg) is attached to a 0.3 m string

Question

1) A rubber stopper with a mass of 26 g (.026 kg) is attached to a 0.3 m string and spun overhead. It is determined that it spins with a velocity of 4.96 m/s. Ignoring the Force of Gravity on the stopper... a. What is the centripetal acceleration? b. What is the centripetal force?

2) A 50 kg runner moving at a speed of 8.8 m/s rounds a bend with a radius of 25 m. a. What is the centripetal acceleration on the runner? b. What is the centripetal force?

3) Racing on a flat track, a 1500 kg car going 32 m/s rounds a curve with a 56 m radius. a. What is the car’s centripetal acceleration? b. What is the car’s centripetal force?

Explanation / Answer

1)

centripetal acceleration , a =v^2/r = 4.96^2/0.3 = 82 m/s2

Centripetal force is , f = ma = 0.026*82 = 2.13 N

2)

centripetal acceleration , a =v^2/r = 8.8^2/25= 3.0976 m/s2

Centripetal force is , f = ma = 50*3.0976 = 154.88 N

3)

centripetal acceleration , a =v^2/r = 32^2/56= 18.285 m/s2

Centripetal force is , f = ma = 1500*18.285 = 27428.57 N

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