hello I\'m having a problem with this question can someone give a hand, if possi
ID: 1487468 • Letter: H
Question
hello I'm having a problem with this question can someone give a hand, if possible can explain step by step, I know for part b we need to find the critical angle, but for part A I don't know how to prove,?????????
Explanation / Answer
for water air interface
critical angle thetac
sinthetac = n2/n1
sinthetac = 1/1.33
thetac = 48.75
here in the problem the angle of incidence in water is greater than thetac
the light will undergo internal reflection
(b)
angle of reflection = angle of incidence = 60 degrees
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.