From the conversion factor, 0.251 Asea X (1 ug/0.01 Asez)-25.1 ug 25.1 g/10 1 2.

Question

From the conversion factor, 0.251 Asea X (1 ug/0.01 Asez)-25.1 ug 25.1 g/10 1 2.51 g/ x 1000 /ml X 1 g/1000 0" 2.51 mg/ml Remember that 1 ug/ul is the same as 1 mg/ml, so you don't really need to multiply through by all of the metric conversion factors Suppose also that 5 1 of another fraction gave an absorbance of 0 097, 10 1 of this fraction gave an absorbance of 0 178, 2011 of this fraction gave an absorbance of 0.317, and 50 1 of this fraction gave an absorbance of 0.653. What is the average value of the protein concentration for this fraction? Again, you can either read the protein amounts off of the graph or use the conversion factor a. 0.097 A002 x 1 0.01-9.7 g 9.7 g/5 . 1.94 .! 1.94 mg/ml b. 0.178 Ase2 x 1 . 17.8 1 7.8 g/ 10 = 1.78 1-1.78 mg/ml c. 0.317 Ae2 X 1 ug/0.01-31.7 ug 31.78 g/20 |s 1.58 .1-1.58 mg/ml The mean of these three values is: (1.94+1.78+1.58y3-1.77 mg/ml In doing this calculation, you cannot use the a beyond the range of the standard curve. Even though the line appears to be linear, you have no way of knowing that the linear relationship continues indefinitely. In fact, most standard curves linearity at high absorbance values or high amounts bsorbance of 0.653 for the 50 1 sample because it is will deviate from

Explanation / Answer

Answer:

In the standard curve, volume fraction and concentration should show a linear relationship.

the mean value for 3 sample has been given 1.77 mg/ml

But the concentration of the 4th sample cannot be calculated on the basis of absorbance. Since absorbance does not show the linear relationship for higher concentration (also mentioned in the given question).

Therefore, the 4th sample can be diluted 10 times so that it can come under the calibration range.

Therefore, after dilution by 10 times, the correct absorbance = 0.097*10=0.97 (total absorbance)

Now from the conversion equation the concentration of this sample (4th sample)= 97/50= 1.94 mg/ml

Now average protein concentration =(1.94+1.78+1.58+1.94)/4= 1.81mg/ml

Therefore, average protien concentration can be 1.81mg/ml

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