two stones a and b experience a collision as shown in the figure. initally, ston

Question

two stones a and b experience a collision as shown in the figure. initally, stone b was at rest and stone a has a horizontal velocity of 2.0m/s heading east. mass a is 5kg and mass of b is 3kg. afer colliion stone a is heading 30 degrees above positive x axis with a final velocity of 1 m/s and stone b is heading below the x-axis at x degrees.

A) make a detailed table of before collision and after collision momenta.

B) calculate the x component of the final velocity of B (use conservation of momentum)

C) calculate the y component of the final vlocity of B

D) what is the angle x that stone be makes with the x-axis after collision?

Explanation / Answer

momentum conservation along x-axis

5*2 + 0 = 5*1*cos(30) + 3*vb*cos(x)

vb*cos(x) = (10 - 4.33)/3 = 1.89 m/s     {Answer of B}

momentum conservation along y-axis

0 = 5*1*sin(30) - 3*vb*sin(x)

vb*sin(x) = 5/6 = 0.834 m/s     {Answer of C}

vb = sqrt(0.834^2 + 1.89^2) = 2.066 m/s

angle x = arctan(0.834/1.89) = 23.810     {Answer of D}

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