Two wires cross each other at 90 degrees as shown. The current in wires 1 is1_1

Question

Two wires cross each other at 90 degrees as shown. The current in wires 1 is1_1 =11A, and the current in wire 2 is 1_2 = 7A. Find the magnitude of the net magnetic field created by two wires at location A that is 5 cm from both wires. The wires and location A all lie on the X-Y plane. 1.60e-005 T 3.54e-005 T 3.84e-005 T 2.04e-005 T 3.10e-005 T A solenoid has a length of 0.2 m and 53 turns. If the current in the windings is 11 What is the magnitude of the magnetic field inside the soleniod? 3.66e-033 T 7.33e-004 T 4.9e-004 T

Explanation / Answer

Magnetic field at A due to wire 1, B1 = oI1/2rA (into the page)

Magnetic field at A due to wire 2, B2 = oI2/2rA (out of the page)

Net magnetic field at A,

Bnet = o(I1 - I2)/2rA = (4 * 10-7) * (11 - 7) / (2 * 0.05) = 1.60 * 10-5 T (into the page)

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