14.43 A 0.0545 kg chunk of an unknown metal that has been in boiling water for s

Question

14.43

A 0.0545 kg chunk of an unknown metal that has been in boiling water for several minutes is quickly dropped into an insulating StyrofoamTM beaker that contains 0.462 kg of water at room temperature (20.0 C). After waiting for a few minutes, you observe that the water's temperature has reached a constant value of 22.0 C.

Part A

Assuming that the StyrofoamTM absorbs a negligibly small amount of heat and that no heat was lost to the surroundings, what is the specific heat of the metal?

c = ________J/(kg*K)

Explanation / Answer

The heat lost for the unknown metal must be equal to heat gain for the water,

Q_water=M_w *C_w*(T_f -T_iw)

Q_metal=M_m*C_m*(T_im - T_f)

Q_water = Q_metal

hence, C_m =(M_w *C_w*(T_f -T_iw))/(M_m*(T_im - T_f))

C_m = 0.9094 J/Kg*K

_____________________________

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