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Problem 2.55 The figure shows the velocity of a train as a function of time. (Fi

ID: 1489762 • Letter: P

Question

Problem 2.55

The figure shows the velocity of a train as a function of time.
(Figure 1)

Part A

At what time was its velocity greatest?

Express your answer as an integer.

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Part B

During what periods, if any, was the velocity constant?

During what periods, if any, was the velocity constant?

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Part C

During what periods, if any, was the acceleration constant?

Check all that apply.

Check all that apply.

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Part D

When was the magnitude of the acceleration greatest?

When was the magnitude of the acceleration greatest?

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Figure 1 of 1

Problem 2.55

The figure shows the velocity of a train as a function of time.
(Figure 1)

Part A

At what time was its velocity greatest?

Express your answer as an integer.

SubmitHintsMy AnswersGive UpReview Part

Part B

During what periods, if any, was the velocity constant?

During what periods, if any, was the velocity constant?

tv=max = s

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Part C

During what periods, if any, was the acceleration constant?

Check all that apply.

Check all that apply.

from t = 90 s to t 108 s from t 65 s to t 83 s from t = 42 s to t 65 s from t = 110 s to t 125 s from t = 0 s to t 42 s

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Part D

When was the magnitude of the acceleration greatest?

When was the magnitude of the acceleration greatest?

from t = 0 s to t 42 s from t = 110 s to t 125 s from t = 42 s to t 65 s from t = 90 s to t 108 s from t 65 s to t 83 s

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from t = 0 s to t 42 s from t = 110 s to t 125 s from t = 42 s to t 65 s from t = 90 s to t 108 s from t 65 s to t 83 s

Figure 1 of 1

Explanation / Answer

PART A)

As per the graph showing here velocity is greatest at t = 48 s

PART B)

when the slope of the velocity time graph is zero then its acceleration is zero hence we will say that its velocity is constant

so here from graph it is between t = 90 s to t = 108 s

PART C)

Acceleration will be constant when slope of velocity time graph will be constant

hence from graph we have

t = 0 to t = 38 s

t = 65 to t = 83 s

t = 90 to t = 108 s

PART D)

Magnitude of acceleration is greatest when the slope of the graph is maximum

so its from the graph we have

t = 65 s to t = 83 s

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